Jun 08, 2014 · Using work energy theorem, Work Done = Change in Kinetic Energy Note: m = mass of object g = acceleration due to gravity h = height v = velocity Therefore mg * h = 1/2mv^2 (As work done = force * distance; initial KE = 0, final KE = 1/2mv^2) He...
1.A ball of mass 0.5 kg is rolling across a table top with a speed of 5 m/s. When the ball reaches the edge of the table it rolls down an incline onto the floor 1.0 meter below (without bouncing) What is the speed of the ball when it reaches the floor? 2. A hot whells car of mass 0.025 kg is traveling on a horizontal track with a velocity of 5.0 m/s.
15. A 5-newton ball and a 10-newton ball are released ... cart B has a mass of 5.0 kilograms. The speed of cart A is 0.33 meters per second after the spring
Get an answer for 'A ball of mass m 1 = 8.0 × 10−2 kg starts from rest and falls vertically downward from a height of 3.0 m. After colliding with the ground, it bounces up to a height of 2.0 m.
A ball of mass 0.2 kg rest on a vertical pole of height 5 m. A bullet of mass 0.01 kg travelling with a velocity v m/sec in a horizontal direction,hits the center of ball. After the collision, the ball and the bullet travel independently. The ball hits the ground at a distance of 20m and the bullet at a distance of 100m from the foot of the post.
To determine the momentum of the ball, substitute the known values for the ball’s mass and speed into the equation. p ball = (0.410 kg)(25.0 m/s) = 10.3 kg · m/s The ratio of the player’s momentum to that of the ball is
4. An owl has a mass of 4.00 kg. It dives to catch a mouse, losing 800.00 J of its GPE. What was the starting height of the owl, in meters? 5. An astronaut with a mass of 110.0 kg visits the moon (which has a different gravitational force than Earth). The astronaut climbs 5.0 m up the ladder into his spacecraft and gains 880.0 J in GPE.